Not likely......but understand what the equation means from a quantitative perspective. In other words....Understand that the rate constant depends on factors such as Activation energy, temperature, and collision frequency. A reaction with a small energy of activation will be fast, hence giving a large rate constant. Slow reactions have high energy of activations with small rate constants. One can plot lnk vs 1/ T in Kelvin and achieve a linear plot. Verify this in any General Chemistry book. The slope of this line allows one to calculate energy of activation. Understanding the theory should be all that you need.