beta oxidation, and oxygen consumption

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anbuitachi

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A Uworld question said B oxidation uses more oxygen than glucose oxidation per ATP produced [id 950]...I'm not sure how this works.. is it because in Beta oxidation, more FADH2 is produced proportional wise to NADH compared to glucose oxidation? [Not sure where else Beta oxidation is using Oxygen]
 
Edit: actually, the calculations are problematic, my bad.
Edit#2: Just to try and make some sense of the question -
One cycle of beta-oxidation produces: 1 FADH2, 1 NADH, 1 acetyl-CoA (3 NADH + FADH2 + GTP) = 2 FADH2 + 4NADH2 + GTP (6 O2 consumed, net 4 + 12 + 1 = 17 ATP)
One molecule of glucose produces: 2 NADH, 2 ATP, 2 acetyl-CoA (3 NADH + FADH2 + GTP) = 8 NADH + 2 FADH2 + 2 GTP + 2 ATP (10 O2 consumed, net 24 + 4 + 4 = 32 ATP)

Now just to make some mathematical sense of it - 10 beta-oxidation cycles produce 170 ATP and consume 60 O2 molecules; 6 complete glucose oxidation cycles = 192 ATP and 60 O2 molecules consumed.
 
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