Bio Bootcamp Q

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flossit

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In a flower, the alleles for plant height are tall (T) and short (t), and the alleles for petal color are red (R) and white (r). A cross between two parents, both short and red, produces a progeny of 3/4 short and red and 1/4 short and white. What are the genotypes of the parents?

Can someone explain?
 
All the kids are short so both parents are homo dom (tt) and the color is classic 3/4 dom pheno and 1/4 homo pheno that goes with both parents being heterozygotes (Rr). Fill out a punnet square for each individual trait and it will become apparent.
 
The question already tells you that both parents are short, so you know the genotype of the parents with respect to height must be tt. That leaves the color - again you are told both parents are red, which means they are either going to be RR or Rr. Looking at the progeny, we see that 3/4th are red and 1/4th are white. Because there are progeny with the recessive trait (rr), we know that both parents must be heterozygotes carrying the recessive allele (you can rule out parents being rr because neither parent is white, and you can rule out RR because you would have all red progeny if either parent had that genotype). Both parents must therefore be Rrtt.

You could also reason out that having progeny which are 3/4th dominant phenotype and 1/4th recessive phenotype is typical of a heterozygote cross (Rr x Rr in this case).
 
I'm trying to construct a punett square on progeny from given information, and what i get does not match with what the parents should be. when i put Rt and Rt, and when i put Rt and rt, i can't put them together. i'm doing something wrong for sure. can you please explain in steps what to do?
 
I'm trying to construct a punett square on progeny from given information, and what i get does not match with what the parents should be. when i put Rt and Rt, and when i put Rt and rt, i can't put them together. i'm doing something wrong for sure. can you please explain in steps what to do?

Remember that a punnet square is always crossing two parents full genotypes - that means for every trait, you are crossing a minimum of 2 alleles for each parent. What you would be crossing here is Rrtt x Rrtt. You don't know if these genes are linked or not, so do two separate punnet squares, one for each trait:

tt x tt (this doesn't really need a punnet square - you already know the outcome - always tt)
Rr x Rr (the outcome of this cross should be RR, Rr, Rr, and rr)

It sounds like you tried to do a more complicated method of figuring out the gametes the parents would produce (each parent has a 50% chance of product a Rt gamete or an rt gamete) and then crossed those...but doing it that way is a lot more difficult because you would have to consider multiple probabilities (that parent 1 produced Rt and parent 2 produced Rt, that parent 1 produced Rt and parent 2 produced rt, that parent 1 produced rt and parent 2 produced rt, etc.). Don't use that method, figure out the individual crosses for each trait first - it's a lot simpler.

Also, I think trying to reverse construct a punnet square from progeny information is just a giant headache. Try to focus on the information given to you about the parents first to figure out the potential crosses that could have taken place, and then use a punnet square at the end to confirm your answer. Doing it the reverse way is unnecessary and convoluted.
 
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