I'm assuming you need an explanation:
Females have XX, males have XY. Since the disease is X-linked recessive, females require two X chromosomes with the same mutation to have the disease, but males require only one X chromosome with the mutation.
Disease frequency in females is 1/1,000,000. In that case, the frequency at which the mutation is present in each X chromosome is 1/1,000 (1/1,000 x 1/1,000 = 1,000,000)
Males have XY, then their disease frequency has to be the same as that of a single X chromosome: 1/1,000