Question: 10,000 IV-drug-users. 1,000 turn out to be infected with HCV. During two years of follow-up 200 patients with HCV die. Also during follow-up 200 IVDU acquire HCV. What is the estimate of annual incidence of HCV over these two years.
Here is my question:
So i know how to calculate the numerator 200 new cases over 2 years = 200/2 = 100
How about the denominator for incidence - why is the answer 9,000?
Did they get the denominator by 10,000 - 200 (HCV death) + 200 (HCV new cases) = 9,000 IVDU at risk for HCV?
Answer by the way is: 100 / 9,000
Just confused about how to factor in deaths when calculating incidence
Here is my question:
So i know how to calculate the numerator 200 new cases over 2 years = 200/2 = 100
How about the denominator for incidence - why is the answer 9,000?
Did they get the denominator by 10,000 - 200 (HCV death) + 200 (HCV new cases) = 9,000 IVDU at risk for HCV?
Answer by the way is: 100 / 9,000
Just confused about how to factor in deaths when calculating incidence