Bohr Hydrogen atom

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Necr0sis713

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I need to clarify my understanding of the Bohr Hydrogen model. So...orbitals closest to the nucleus have the highest energy? I see that the energy (eV) is proportional to the inverse of the orbital squared; meaning a smaller denominator gives bigger energy.

So, does this mean that energy transitions from 2-1 as opposed to say...4-3 are more energetic (release lower wavelength photons)?

What are they using as a reference here? An electron in the orbital relative to a positively charged nucleus? so, since electrons move to HIGHER potential, being closer to the nucleus means a higher energy orbital?

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