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There is a question in organic chem odyssey that asks which halide has the greatest boiling point. The choices are 2-bromobutane, 2-chlorobutane, 2-fluorobutane, 2-iodobutane, and all about equal.
Why is the answer 2-iodobutane. It makes sense that iodobutane has more electrons and it's more polarizable, but doesn't fluorobutane have a bigger dipole?
Thanks!
Why is the answer 2-iodobutane. It makes sense that iodobutane has more electrons and it's more polarizable, but doesn't fluorobutane have a bigger dipole?
Thanks!