- Joined
- May 29, 2010
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What is going on here?
It is obvious from the graph that A has a larger capacitor
But why does B have a larger resistor??
This doesn't seem to make any sense because of the formula of q=VC
A larger resistor should increase the voltage (V=IR) and INCREASE the value of q
Why am I wrong here??
It is also clearly not a factor of charging time as B has plateaued out
It is obvious from the graph that A has a larger capacitor
But why does B have a larger resistor??
This doesn't seem to make any sense because of the formula of q=VC
A larger resistor should increase the voltage (V=IR) and INCREASE the value of q
Why am I wrong here??
It is also clearly not a factor of charging time as B has plateaued out