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Q 157.png


Solution:


Since DE, FG, and AC are parallel, the triangles are similar, so we can write a proportion:

DFEG=FAGC\frac{DF}{EG} = \frac{FA}{GC}EGDF=GCFA
Let DF = x
Then FA = 2x + 3, EG = 5, and GC = 15.

x5=2x+315\frac{x}{5} = \frac{2x + 3}{15}5x=152x+315x=10x+1515x = 10x + 1515x=10x+155x=155x = 155x=15x=3x = 3x=3
âś… Answer: C (3)


 

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