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At plasma concentrations of glucose higher than occur at transport maximum (Tm), the
(A) clearance of glucose is zero
(B) excretion rate of glucose equals the filtration
rate of glucose
(C) reabsorption rate of glucose equals the
filtration rate of glucose
(D) excretion rate of glucose increases with
increasing plasma glucose concentrations
(E) renal vein glucose concentration equals
the renal artery glucose concentration
answer below
The answer is D [III B; Figure 5-5]. At concentrations greater than at the transport maximum
(Tm) for glucose, the carriers are saturated so that the reabsorption rate no longer
matches the filtration rate. The difference is excreted in the urine. As the plasma glucose
concentration increases, the excretion of glucose increases. When it is greater than the
Tm, the renal vein glucose concentration will be less than the renal artery concentration
because some glucose is being excreted in urine and therefore is not returned to the
blood. The clearance of glucose is zero at concentrations lower than at Tm (or lower than
threshold) when all of the filtered glucose is reabsorbed, but is greater than zero at concentrations
greater than Tm.
why is B not the right answer too? check out the graph here (http://images.slideplayer.com/31/9741800/slides/slide_23.jpg) the filtration and excretion slopes are equal to each other after Tm is reached.
also i feel like D is not that correct. even if plasma [glucose] increases, would excretion rate really increase? i think that excretion rate would depend on how much glucose can be filtered (filtration rate). would a higher plasma [glucose] increase filtration rate?
(A) clearance of glucose is zero
(B) excretion rate of glucose equals the filtration
rate of glucose
(C) reabsorption rate of glucose equals the
filtration rate of glucose
(D) excretion rate of glucose increases with
increasing plasma glucose concentrations
(E) renal vein glucose concentration equals
the renal artery glucose concentration
answer below
The answer is D [III B; Figure 5-5]. At concentrations greater than at the transport maximum
(Tm) for glucose, the carriers are saturated so that the reabsorption rate no longer
matches the filtration rate. The difference is excreted in the urine. As the plasma glucose
concentration increases, the excretion of glucose increases. When it is greater than the
Tm, the renal vein glucose concentration will be less than the renal artery concentration
because some glucose is being excreted in urine and therefore is not returned to the
blood. The clearance of glucose is zero at concentrations lower than at Tm (or lower than
threshold) when all of the filtered glucose is reabsorbed, but is greater than zero at concentrations
greater than Tm.
why is B not the right answer too? check out the graph here (http://images.slideplayer.com/31/9741800/slides/slide_23.jpg) the filtration and excretion slopes are equal to each other after Tm is reached.
also i feel like D is not that correct. even if plasma [glucose] increases, would excretion rate really increase? i think that excretion rate would depend on how much glucose can be filtered (filtration rate). would a higher plasma [glucose] increase filtration rate?