Buoyancy question

[kabtq9s]

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This is a basic question, but I just want to double check, any kind soul willing to solve it?


-If the density of an object is 3/7 of the density of fluid its in, how much of it will be submerged? and why?

Thanks

 

[NonTraditional3]

I think the ratio, obj:fluid, will give your percentage of submerged volume. Multiply this value by object volume to get fluid displaced and volume submerged (they are equal)

 

[Perpetually]

I do not immediately recall the formula.

So let's reason it out.

If substance A is at all submerged (and not totally afloat) in substance B, then the ratio of the density of A/B must be > 1.

Therefore, if an object has a density ratio of 3/7 to the density of the fluid, then 3/7 of it will be submerged and 4/7 of it will be above the fluid.

Hope that helps.

 

[ThirdEye]

Density obj/density fluid x 100 = % submerged

3/7 x 100 = .........