Calculating kcal of one ATP

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hemoglobincell

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So here's how I've tried calculating the kcal of one ATP:
(1 mol glucose/32 mol ATP)(180. g/mol glucose)(4 kcal/g glucose) = 22.5 kcal/mol ATP

The real answer is 7.3 kcal/mol ATP. What am I doing wrong?
 
So here's how I've tried calculating the kcal of one ATP:
(1 mol glucose/32 mol ATP)(180. g/mol glucose)(4 kcal/g glucose) = 22.5 kcal/mol ATP

The real answer is 7.3 kcal/mol ATP. What am I doing wrong?

I guess you don't know the rules of the forums...
 
I guess you don't know the rules of the forums...

Care to elaborate? Had a question today that hinged on knowing the kcal/mole of 1 ATP but it's been so long since I had general chemistry I couldn't figure it out.
 
I know this looks and sounds like a homework problem. I can assure you it is not. I just want to know for my own knowledge. I got a question on an NBME exam that hinged on knowing the kcal/mol of ATP. I am an MS2 and have not had general chemistry in a while, although I suspect my calculations are right and my problem is with something else. If you don't wish to answer my question then fine, just let the thread die. I can assure you this is not a homework problem.
 
I know this looks and sounds like a homework problem. I can assure you it is not. I just want to know for my own knowledge. I got a question on an NBME exam that hinged on knowing the kcal/mol of ATP. I am an MS2 and have not had general chemistry in a while, although I suspect my calculations are right and my problem is with something else. If you don't wish to answer my question then fine, just let the thread die. I can assure you this is not a homework problem.
And you posted this in Pre-Allo instead of the MCAT forum or something because...?
 
So here's how I've tried calculating the kcal of one ATP:
(1 mol glucose/32 mol ATP)(180. g/mol glucose)(4 kcal/g glucose) = 22.5 kcal/mol ATP

The real answer is 7.3 kcal/mol ATP. What am I doing wrong?

you're messing up because the energy of combustion of glucose won't give you the energy to hydrolyze atp.
 
you're messing up because the energy of combustion of glucose won't give you the energy to hydrolyze atp.

This makes sense. So if there were no loss of energy in the process my equation would work, but instead it overestimates...

Well I'm going to leave this question alone then. Everyone in my class guessed on it lol. Anyway, thanks for your help.
 
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