can u solve this?

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kishanji

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find all the values of x at which the

f(x)=(x^2-1)/(x^3-x^2-2) is discontinuous?

i think there is something wrong with the question !
 
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set the denominator = 0 and solve.......not sure how to solve it tho.....sorry.
i.e. find the vertical asymptote...according to a graphing calc shud b about 1.69.....any one know a short cut to solving cubic equations.....wish we could use our calculators 🙂
 
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the given answer is 0, 1, -2 which i think is totally bias. and there is no way to solve that cubic denominator .. not atleast by any known method.
 
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f(x)=(x^2-1)/(x^3-x^2-2) is discontinuous?

can you just factor out the x from the den and set it = to 0?

x(x2-x)-2 = 0
then x-2 =0 and (x2-x )= 0
x = 2 and x2 = x , x must be a 0 or 1
 
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x^3 - x^2 - 2 = 0 to get discontinued line

0, -1, -2 .. all wrong ..
Simply plot in the numbers and u won't get 0

There is a chapter in the calculus textbook just to solving these kind of problems. Something like Ax + Bx +Cx etc.
 
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The answer is

1.6956207695598597

This is a tough one. I will admit solving cubic equations is probably non going to be on the PCAT. I wouldnt worry about it.
 
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phew.....i was about to go nuts....just one of those people who have to answer the damn question....or it bugs me for the rest of my day....hope i won't do that on the pcat tho...😀

Lasche: if i remember rite you can't solve it ur way;u can only factor if
Ax+Bx+Cx+Dx.....=0 in this case it would equal 2.....but if there are an even number of terms u can factor a common term in each n then set each equal to zero....kinda like a quadratic......
 
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hey infinitiiz......do u have a short cut to solving the cubic eqs. .....please let us know.....after all sharing is caring 👍 ......thanks
 
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there is no way to solve the denominator. the person trying to teach you about solving this kind of denominator is just making some non-mathematical "blunders". I was concerned bcz this was the first problem of the practice exam and i took 5 minutes trying to solve this and was not able to solve the last 2 problems within time period.
 
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