chads chemistry help question!

[DMDftw]

So I'm having a hard time understanding how to do this question.

If the rate of disappearance of H2 is 6M/min, then what is the rate of appearance of NH3?
N2 (g) + 3H2 (g) --> 2NH3 (g)

the answer is 4M/min.


Thanks!!

chad's explanation was
"∆[NH3]/∆t = (6M/min)(2 mol NH3/3 mol H2) = 4M/min"

but i dont get how he set that up!?

---

Members don't see this ad.

 

[wizi]

So I'm having a hard time understanding how to do this question.

If the rate of disappearance of H2 is 6M/min, then what is the rate of appearance of NH3?
N2 (g) + 3H2 (g) --> 2NH3 (g)

the answer is 4M/min.


Thanks!!

chad's explanation was
"∆[NH3]/∆t = (6M/min)(2 mol NH3/3 mol H2) = 4M/min"

but i dont get how he set that up!?

He uses coefficient.

 

[Golfguy]

So I'm having a hard time understanding how to do this question.

If the rate of disappearance of H2 is 6M/min, then what is the rate of appearance of NH3?
N2 (g) + 3H2 (g) --> 2NH3 (g)

the answer is 4M/min.


Thanks!!

chad's explanation was
"∆[NH3]/∆t = (6M/min)(2 mol NH3/3 mol H2) = 4M/min"

but i dont get how he set that up!?

2 moles of product appear for every three of H2 that disappear. Stoichiometric ratios at work here....

 

[DMDftw]

haha thanks dumb question

i was wondering why he set up ∆[NH3]/∆t = (6M/min)
but i got it now.