Question: A laptop draws 0.6 A of current over 1 hour. How much charge was delivered to the laptop?
Solution: 1 Amp is 1 C/second, meaning that in 1 hour, 1 Amp would draw 60 * 60 = 3600 C of charge. Since the laptop only draws 0.6 A, 0.6 * 3600 = 2160 A.
Isn't it Q = I/t = 0.6 A/3600 sec?
Solution: 1 Amp is 1 C/second, meaning that in 1 hour, 1 Amp would draw 60 * 60 = 3600 C of charge. Since the laptop only draws 0.6 A, 0.6 * 3600 = 2160 A.
Isn't it Q = I/t = 0.6 A/3600 sec?
Last edited:
