Chemistry Equilib Problem

[eatkabab]

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3 mols of CO2(g) in a 2L container at 400K. At equilibrium, the CO2 is 20% dissociated. what is the value of K?

2CO2(g) --> 2CO(g) + O2(G)


this is how I would do the problem:

[CO]^2[O2] / [CO2]^2

3(.2) = .6

[.6]^2[.3] / [2.4]^2 = 0.0188 = K

apparently this is incorrect. I think the container volume and temperature are extraneous...


please help 🙂 thank you very much to everyone on sdn...

 

[DDSelin2mori]

For finding K you can only use concentration not # of moles. What you r using is number of moles, so just divide them by 2 which is the volume of container:

(0.3)^2(0.15)/ (1.2)^2

 

[eatkabab]

For finding K you can only use concentration not # of moles. What you r using is number of moles, so just divide them by 2 which is the volume of container:

(0.3)^2(0.15)/ (1.2)^2

holy lordy I feel like a *****... thank you very much. wish I could delete this thread. sorry to pollute the forum 🙁