Chemistry Problem

This forum made possible through the generous support of SDN members, donors, and sponsors. Thank you.

winterhot

Full Member
10+ Year Member
Joined
Jan 31, 2009
Messages
46
Reaction score
0
Hi all, I have 2 chemistry problems that I don't quite understand. Please help me.

For the reaction:
AgCl(s) + 2NH3 (aq) ---> Ag(NH3)2+ (aq) + Cl- (aq), the equilibrium constant K= 4x10^-3, which of the following statements is true?
(Ksp for AgCl is 1x10^-10)

a. the addition of NH3 decreases the solubility of AgCl
b. AgCl is more soluble in aqueous NH3 than in water
c. AgCl is more soluble in aqueous solution containing Cl- than in water.
d. AgCl is less soluble in aqueous NH3 than in water

I thought the answer is D since AgCl is insouble but the real answer is B. Can someone please explain to me?


The bond length is Cl2 is 1.99 A. The distance separating two adjacent carbon nuclei in diamond is 1.54 A. Based on these data, what is the length of the C-Cl bond in the compound CCl4?

a. 3.53
b. 2.53
c. 2.16
d. 1.76
e. 1.54

I didn't really know how to do this one. I added both number and got A but the real answer is D. Don't know how.

Thanks in advance.

Members don't see this ad.
 
Hi all, I have 2 chemistry problems that I don't quite understand. Please help me.

For the reaction:
AgCl(s) + 2NH3 (aq) ---> Ag(NH3)2+ (aq) + Cl- (aq), the equilibrium constant K= 4x10^-3, which of the following statements is true?
(Ksp for AgCl is 1x10^-10)

a. the addition of NH3 decreases the solubility of AgCl
b. AgCl is more soluble in aqueous NH3 than in water
c. AgCl is more soluble in aqueous solution containing Cl- than in water.
d. AgCl is less soluble in aqueous NH3 than in water

I thought the answer is D since AgCl is insouble but the real answer is B. Can someone please explain to me?


The bond length is Cl2 is 1.99 A. The distance separating two adjacent carbon nuclei in diamond is 1.54 A. Based on these data, what is the length of the C-Cl bond in the compound CCl4?

a. 3.53
b. 2.53
c. 2.16
d. 1.76
e. 1.54

I didn't really know how to do this one. I added both number and got A but the real answer is D. Don't know how.

Thanks in advance.

for first question Agcl make complex compond [Ag(NH3)2]Cl that means more soluble.
for second question just imagine two cycle that have a commen area.
1.99/2~1
1.54/2= 0.77
1+.077=1.77
 
you were right about AgCl being insoluble.. in water. In NH3, as Danny said it forms a complex ion so therefore it would be more soluble in NH3 than in H2O where it's barely soluble at all (you can tell by the ksp values too... its higher in NH3 meaning its more soluble in it)

and for the second one think of a bond going from the center of one to the center of the other, thats why danny divided it by 2. So you basically get the radius for each one and add the two together!
 
for the first question both people were right that AgCl being insoluble.. in water, since the Ksp is 1x10^-10. So this means that the concentration of [Ag+] and [Cl-] is equal to 1x10^-10. However, in the mother rxn we are not in water but instead NH3 and the K=4x10^-3, therefore the concentration of AgCl has gone up since this is a much bigger K value. Therefore, the answer is B) that AgCl is more soluble in aqueous NH3 than in water

For the second question, you need have the bond length of a Cl and half a bod length of a C. Therefore to solve, you would set it up like this; (1.99+1.54)/2=1.77
 
Top