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Question:
What is the % yield of 0.112g S02 obtained from the combination of 0.0781g of CS2 according to the reaction CS2 + 3O2 --> CO2 + 2SO2
I know the equation is AY/TY X 100%. I'm pretty sure the actual yield is 0.112g S02 but how do I go about getting the theoretical yield I need for the denominator?
What is the % yield of 0.112g S02 obtained from the combination of 0.0781g of CS2 according to the reaction CS2 + 3O2 --> CO2 + 2SO2
I know the equation is AY/TY X 100%. I'm pretty sure the actual yield is 0.112g S02 but how do I go about getting the theoretical yield I need for the denominator?