chemistry

[arpitpatel86]

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The following reaction is secnod order with respect to W
and second order with respect to X. If the concentration
of W and X are doubled what happens to the rate of
the reaction?​

W + X → Y + Z

 

[userah]

damn it stupid thing messed up. gotta retype it now...

ok i believe this is how it goes.

This is how the reaction rate works.
aA + bB -> cC + dD

the reaction rate for this would be: rate = k [A]^a ^b

so for the example you gave where concentrations are doubled for both: rate = k[W]^2 [X]^2

if you increase ONE of the reactants by two, the rate increases by a factor of 4 (2^2). If you increase BOTH of the reactants by two like the problem states, the rate would increase by a factor of 16 (2^2) * (2^2)

hope that helps =)

 

[doc3232]

damn it stupid thing messed up. gotta retype it now...

ok i believe this is how it goes.

This is how the reaction rate works.
aA + bB -> cC + dD

the reaction rate for this would be: rate = k [A]^a ^b

so for the example you gave where concentrations are doubled for both: rate = k[W]^2 [X]^2

if you increase ONE of the reactants by two, the rate increases by a factor of 4 (2^2). If you increase BOTH of the reactants by two like the problem states, the rate would increase by a factor of 16 (2^2) * (2^2)

hope that helps =)

Well-explained.

 

[userah]

i don't understand why the editing won't fix the issue but it should read
rate = k[A]^a ^b

in case it still doesn't work...the B in the bracket should be capitalized

lol still not working...really odd =(

 

[Zerconia2921]

i don't understand why the editing won't fix the issue but it should read
rate = k[A]^a ^b

in case it still doesn't work...the B in the bracket should be capitalized

lol still not working...really odd =(

Userah your awsome! 👍 great explanation.

 

[userah]

hahaha thanks =) although i'll be honest, google helped a little =P