It was 13, but it was confusing becuase they had cytochrome C into a two step reaction it seemed.
Cyt C --> Cyt a/3
Cyt a/a3 --> O2
I dont really understand what it is trying to show.
My interpretation is that they're trying to separate out where CO
actually plays a role.
As far as I'm aware, CO binds to cytochrome C oxidase, inhibiting it.
Cyanide binds to cytochrome aa3, preventing the transfer of electrons to molecular oxygen.
That distinction is exceedingly high-yield.
I have that annotated into my FA. I can't entirely recall where I had seen that. It may have been FA Q&A, but I specifically remember that CO was the
wrong answer regarding "binding to cytochrome C and inhibiting the transfer of electrons to molecular oxygen." That was specifically cyanide,
not CO.
All of the following is stuff I had annotated directly into my FA from USMLE Rx and FA Q&A:
Complex I = NADH dehydrogenase
Complex II = succinate dehydrogenase
Complex III = cytochrome bc1 complex (Q-cycle)
Complex IV = cytochrome C oxidase / cytochrome oxidase aa3
Rotenone is a
competitive inhibitor of NADH dehydrogenase, the first component of e- transfer in the e- transport chain.
For succinate dehydrogenase, FAD --> FADH2 (requires B2).
Antimycin A binds to cytochrome C
reductase and prevents e- transfer from cytochrome b to cytochrome c (I've interpreted this as antimycin A knocking out complex III).
CN- binds to Fe
3+ in cytochrome oxidase aa3, preventing transfer of e- to molecular O2.
All of these agents induce lactic acidosis (anion-gap acidosis). Although CN- poisoning may decrease O2 saturation, laboratory studies show
near normal O2 saturation. This is in contrast to CO, which has increased affinity for Hb, so O2 saturation would be decreased with CO poisoning. And with
CN- poisoning, selectively, there is
increased venous O2 saturation, because cells cannot use O2 (decreased venous-arterial O2 difference).