Two guns, separated by five meters and pointed at each
other, are tilted so that each gun points at an angle above
the horizontal. Both guns are fired simultaneously, with
each bullet leaving its gun at a speed of 250 m/s. The bullets
collide inelastically in midair, falling together to the
ground.
How much time elapses between the firing
of the guns and the collision of the two bullets?
I tried to use the equation vy = v0y - gt
So I got 25sintheta = t
However, the answer is apparently 0.01/costheta.
If someone could explain, that would be great!
other, are tilted so that each gun points at an angle above
the horizontal. Both guns are fired simultaneously, with
each bullet leaving its gun at a speed of 250 m/s. The bullets
collide inelastically in midair, falling together to the
ground.
How much time elapses between the firing
of the guns and the collision of the two bullets?
I tried to use the equation vy = v0y - gt
So I got 25sintheta = t
However, the answer is apparently 0.01/costheta.
If someone could explain, that would be great!