you did the punnett square correctly but you didn't interpret the results correctly. one daughter is color blind and the other one is a carrier. So, half the daughters are colorblind. The answer would be 25% if they asked the probability of their first CHILD being a colorblind daughter. check out the other punnett square problems, you'll see what i mean.

you did the punnett square correctly but you didn't interpret the results correctly. one daughter is color blind and the other one is a carrier. So, half the daughters are colorblind. The answer would be 25% if they asked the probability of their first CHILD being a colorblind daughter. check out the other punnett square problems, you'll see what i mean.

wait a minute, why is half the daughters colorblind . One is carrier Cc (normal)
and the other one is cc colorblind . I understand with the probability scenario, but how do we get half of the daughters colorblind.

Because the other 2 children in your square are SONS and the question asks about DAUGHTERS!

It wants to know the % of colorblind DAUGHTERS not children. So you only look at the two daughters. Of the two daughters, one is colorblind. 1 out of 2 = 50%.