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What is the max concentration of F- Ions that could be present in .032M Ba(NO3)2? (KSP BaF2- 3.2x10^-8)
The Ksp=[Ba][F]^2 But since there is a common Ion the Ba become .032M so to find [F] we have 3.2x10^-8=[.032][x]^2. Then 1x10^-6=[x]^2 and then square root and get [x]= 1x10^-3
Ok but here is my question. If there was not a common Ion present and just say the Ksp was given and we wanted molar solubility the expression would be Ksp= [x][2x]^2= 27x^4.
I do not understand why if there is a common ion why the expression is x^2 and not 2x^2....
The Ksp=[Ba][F]^2 But since there is a common Ion the Ba become .032M so to find [F] we have 3.2x10^-8=[.032][x]^2. Then 1x10^-6=[x]^2 and then square root and get [x]= 1x10^-3
Ok but here is my question. If there was not a common Ion present and just say the Ksp was given and we wanted molar solubility the expression would be Ksp= [x][2x]^2= 27x^4.
I do not understand why if there is a common ion why the expression is x^2 and not 2x^2....