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I may be wrong, but when I was answering this question, I thought both compounds were bases because of the hydroxyl group, so reacting both with bases would yield the same result?
The compounds are weak acids. When dissolved in ether, the stronger of the two (aka the one with the lower pka) will react with NaOH to form its alkali salt and go into the aqueous layer. The stronger acid will be the phenol, compound I.
Also known (by IUPAC) as 4-methylphenol.Compound one isn't phenol. Looks like toluene with a para hydroxyl group.
Both of these 2 compounds, regardless of their specific nomenclature, are alcohols (a hydroxyl group bond to a carbon).
IUPAC said:Alcohols - Compounds in which a hydroxy group, –OH, is attached to a saturated carbon atom R3COH. The term 'hydroxyl' refers to the radical species, HO..