Compression of a gas

This forum made possible through the generous support of SDN members, donors, and sponsors. Thank you.

pbure9

Full Member
10+ Year Member
15+ Year Member
Joined
Jul 18, 2008
Messages
272
Reaction score
2
So I've been having some problems with this whole concept mainly bc I see that different sources have different formulas for this (relating heat and work)...

Anyway, my question is related to destroyer 47 in the chem. If a gas is compressed from 40 to 16 liters at 4 atm what is the work?

If a gas is compressed, that means that the system is doing the work on the gas (as opposed to expansion where the gas is doing the work), so shouldn't work be negative not positive?

Thanks guys

Members don't see this ad.
 
In thermodynamics negative work means that the system loses energy. Compression of gas increases the internal energy and therefore the work is positive.
 
Formula for work is W= -P (delta V)

so that mean when it is compressed, our final volume is less than initial so the change is negative giving us positive work.
 
In thermodynamics negative work means that the system loses energy. Compression of gas increases the internal energy and therefore the work is positive.

yes, thats why you dont mix chemistry and physics, negative means positive and positive means negative
 
Members don't see this ad :)
So I've been having some problems with this whole concept mainly bc I see that different sources have different formulas for this (relating heat and work)...

Anyway, my question is related to destroyer 47 in the chem. If a gas is compressed from 40 to 16 liters at 4 atm what is the work?

If a gas is compressed, that means that the system is doing the work on the gas (as opposed to expansion where the gas is doing the work), so shouldn't work be negative not positive?

Thanks guys

i think where you're getting off track on this is that you're not realizing that the gas IS part of the system. when the gas is compressed, the surrounding is doing work on the system.

-work is if the system is doing work. +work is if something is doing work on the system
 
So what is correct then?

well its on the right track but using "internal energy" just totally changes things. the internal energy of the system can increase even if doing work if the heat transfer into the system is larger than the work done being done by the system.

energy lost by work + energy gain by heat = total internal energy

w=-pdeltav is more fitting
 
Last edited:
My statement is correct..and yes the gas is part of the system and is doing work on the surrounding. The reason i used the word energy is because the question states that heat is released.

It's all about convention.
 
Last edited:
heat given off doesnt necessarily mean work is positive (cant just pick positive answer if you see "heat is given off"), unless the problem specifically says temperature stayed constant as well. constant temperature = constant kenetic energy = constant internal energy. internal energy of gas = kenetic energy of gas. delta U = q + w.

delta U = 0 = q = -w, THEN heat given off will always = positive work. otherwise, in a non isothermal expansion/compression, negative heat doesnt always equal positive work.

I edited that part out when i realized non isothermal conditions.
 
Top