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So I found a thread in 09' answering this question partially so please don't get mad. I used the search function.
For the d-block (transition metal) electron configurations, when the neutral transition metal forms a cation, does it ALWAYS lose it's 4s orbitals first?? I want to place a lot of emphasis on the word ALWAYS.
For instance, I know the exceptions Cr and Cu which have 4s1 3d5 and 4-s1 3-d10 lose the 4s electron firms when forming Cr+ and Cu+ respectively, but what if, say, you wanted the e- configuration for Cobal cation (Co=3)
neutral cobalt is [Ar]4s2 3-7
so would Co+3 be [Ar]3d6
Again, do we ALWAYS lose the 4s electrons before we remove any 3d electrons when forming transition metal cations? Thanks!😀
For the d-block (transition metal) electron configurations, when the neutral transition metal forms a cation, does it ALWAYS lose it's 4s orbitals first?? I want to place a lot of emphasis on the word ALWAYS.
For instance, I know the exceptions Cr and Cu which have 4s1 3d5 and 4-s1 3-d10 lose the 4s electron firms when forming Cr+ and Cu+ respectively, but what if, say, you wanted the e- configuration for Cobal cation (Co=3)
neutral cobalt is [Ar]4s2 3-7
so would Co+3 be [Ar]3d6
Again, do we ALWAYS lose the 4s electrons before we remove any 3d electrons when forming transition metal cations? Thanks!😀