DAT bootcamp chemistry question

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bustakorce1

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I don't understand why C is the correct answer. I look at the solution given but I still don't understand it. Here is the question and answer options.

A small amount of aqueous NH3 is added to a solution of Cu2+ and a precipitate forms. However, when excess aqueous NH3 is added, the former precipitate dissolves. Which statement best explains why the precipitate dissolves with excess aqueous NH3?

  • A Cu2+ is reduced to Cu+
  • B. Cu2+ is oxidized to Cu3+
  • C. Cu2+ forms a complex ion with NH3
  • D. NH3 acts as a Bronsted-Lowry base to dissolve the acidic precipitate
  • E. The activation energy to react with the precipitate is overcome with excess NH3
 
Choice C is correct, why?

I don't know, but I do know this is the only complicated reaction of this kind with excess nh3 with Cu
 
This is the solution given as to why C is correct, I don't understand it.

Complex ions are those such as Cu(NH3)42+. The water molecules that normally surround a cation are replaced with some other electron pair donor (NH3 in this case). With excess ammonia, it is possible to form a complex ion with the copper ion. Complex ions tend to be very colorful as well.
 
Bump! Can someone explain this problem please??
 
it turns out that when the solution is dilute the Cu2+ reacts with water instead of NH3, forming Cu(OH)2 solid, and when you add xs NH3 it forms a complex ion that is aqueous. check out the attachment
 

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Ok so Cu(OH)2 is the precipitate that initially forms. I see. I didn't know hydroxide salts are insoluble
 
Ok so Cu(OH)2 is the precipitate that initially forms. I see. I didn't know hydroxide salts are insoluble

-OH is only soluble with group 1A alkali metals and Ca2+ Ba2+ and Sr2+ according to the solubility rules, so Cu(OH)2 is a solid in a solution
 
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