dat destroyer gen chem #31

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yahoogoogle

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I thought that to convert liter atm to J there should be a conversion factor of 101, and so that would make the asnwer choice to be c (-10KJ). what do you guys think?
 
this question is simple thermodynamics question.

you need to take the numbers and just plug in to the following equation:

W= -(P)(change in volume) where P= 4 atm and and the change in volume is -16 liters.

no need to convert to nothing, don't complicate yourself and everybody else. this is the easiest problem in destroyer.
 
PLease don't take this the wrong way but if someone has trouble with a problem it's not appropriate to say that it's the easiest problem; maybe for you but not for others. Some people find it rather insulting.
Best,
Dan
 
PLease don't take this the wrong way but if someone has trouble with a problem it's not appropriate to say that it's the easiest problem; maybe for you but not for others. Some people find it rather insulting.
Best,
Dan

i didn't try to insult anybobody, and if i did i am sorry, just tried to help, that is it.
 
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this question is simple thermodynamics question.

you need to take the numbers and just plug in to the following equation:

W= -(P)(change in volume) where P= 4 atm and and the change in volume is -16 liters.

no need to convert to nothing, don't complicate yourself and everybody else. this is the easiest problem in destroyer.


thanks for the help.

units don't match though. L atm is not the same as joul. you need to multiply whatever you get by 101 to get energy in joul.
 
The reason I think units don't matter here is because:
W = -P(change in Volume) = f x d = Change in KE
Kinetic Energy is measured in Joules, so I think that's why it works out.