DATQVAULT error?

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Jab1113

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A single human cell undergoes mitosis. The resulting cell(s) proceed(s) through another round of mitosis. How many cells exist including the initial cell? (Assume no abnormalities occur)

  • A.
    2 cells.


  • B. [Correct]
    4 cells.


  • C. [Yours]
    8 cells.


  • D.
    12 cells.


  • E.
    16 cells.


I really dont understand this question can somebody please explain this
 
The key here is that the cell goes through mitosis twice. The single cell becomes two after it undergoes mitosis the first time. The resulting cells (two) go through mitosis again (they double) and become four.
 
The key here is that the cell goes through mitosis twice. The single cell becomes two after it undergoes mitosis the first time. The resulting cells (two) go through mitosis again (they double) and become four.

oh duh wow. i thought i had to count every single cell that went through mitosis which came out to 7....thanks
 
The key here is that the cell goes through mitosis twice. The single cell becomes two after it undergoes mitosis the first time. The resulting cells (two) go through mitosis again (they double) and become four.

Correct answer, but incorrect explanation. The question asks you to count the initial cell as well.

The initial cell undergoes mitosis and this produces an additional cell. At this point there are 2 cells.

The question then implies that ONLY the newly formed cell undergoes mitosis. The newly formed cell produces 2 additional cells.

1+1+2=4.

It's an easy question but the wording is tricky. I doubt the actual exam will be this unclear.
 
The question states "The resulting cell(s)" meaning the products of the first mitosis- two cells. These two cells create two more cells in mitosis and in the end four cells exist. I do not believe that this question asks you to count the different cells that existed for a transient time, in this case their would be 7. If you only thought that the one product would undergo mitosis there still would be 5 different cells existing, not four; the initial cell, the initial cell after it had undergone mitosis, its product, it's product after mitosis, and it's product's product.
 
The question states "The resulting cell(s)" meaning the products of the first mitosis- two cells. These two cells create two more cells in mitosis and in the end four cells exist. I do not believe that this question asks you to count the different cells that existed for a transient time, in this case their would be 7. If you only thought that the one product would undergo mitosis there still would be 5 different cells existing, not four; the initial cell, the initial cell after it had undergone mitosis, its product, it's product after mitosis, and it's product's product.

you're right, that's my bad.
 
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