Destroyer biology problem #534

[jz123]

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I understand that statement 1 in question #534 is correct, however, I don't get why statement 2 is also correct.
In anaphase II, can both of the daughter cells produced from meiosis I undergo non-disjunction? If this happens, would there be 4 abnormal daughter cells produced at the end of meiosis II?

 

[Roy Williams]

Here is at 1: http://study.com/cimages/multimages/16/nondisjunction_meiosisI.png

Here is at 2: http://study.com/cimages/multimages/16/meiosisII_nondisjunction.png

If nondisjunction were to happen in anaphase II in both cells, then all four daughter cells would be abnormal. But it is more likely that if it doesn't happen in anaphase I and it does in anaphase II, it will only happen in 1 cell and not both, resulting in two normal daughter cells and two that are aneuploidy.

 

[rak173]

Non-disjunction during Mitosis results in 2n+1 and 2n-1? Is this correct?

 

[Roy Williams]

Non-disjunction during Mitosis results in 2n+1 and 2n-1? Is this correct?

Correct

 

[DAT Destroyer]

I understand that statement 1 in question #534 is correct, however, I don't get why statement 2 is also correct.
In anaphase II, can both of the daughter cells produced from meiosis I undergo non-disjunction? If this happens, would there be 4 abnormal daughter cells produced at the end of meiosis II?

What you are saying is correct, but it is a very rare event. The question in the Destroyer was based on more commonly occurring situations.

The event you are describing has a very low probability of occuring.

Hope this helps.