Destroyer-boiling points

[Vsno123]

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destroyer (2011) gen chem #252

Arrange the following in order of correct boiling point:
H2S, H20, H2Se, H2Te

c) H20 > H2S > H2Se > H2Te
d) H20 > H2Te > H2Se > H2S <-answer

This questions is so stupid! I chose C because dipole-dipole plays a bigger role in boiling point than London dispersion forces...so by looking at electronegativity S > Se >Te.

Thoughts? Does anybody think this will actually be on the real test?

 

[Demps]

H20 has hydrogen bonding, hence the highest boiling point.

the other three choices only have london disperson, van der waals whatever.
In that case, higher molecular weight wins due to greater surface area.

so d is correct.

Chad's quiz had something like this too. so I would know it.

It is always a possibility that it might show up

 

[Vsno123]

I never got a chance to watch Chad's videos. Dipole dipole moments are part of Van der Waals too but the London dispersion forces play a greater role because the molecular weights are so much bigger?