Destroyer G-Chem # 88 - Catalyst

[PD3]

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Hello all,

The question states that the specific rate constant is affected by a catalyst. I thought the rate constant was not affected by a catalyst. Or am I confusing that with Keq?

Thanks.

 

[levyusupov]

if u just think it through, it will make sanse !

catalyst make the reaction goes fater, yes?

thus, if the reaction completed faster, hence the rate of the rxn is faster. so,since the rate is constant dependent, the specific rate constant will change with addition of catalyst !!!!, if it still does not make sanse write the eqn of rate and solve for the K!

and yes, u do confuse with Keq, because ONLY temprature change the the eqlbm constant, Keq.

hope it make sense !!!

 

[Clubby]

I also want to know this as well. I read later on that enzymes DON't affect the specific rate constant, so I don't have a straight answer on the matter either.

 

[drteeth]

I also want to know this as well. I read later on that enzymes DON't affect the specific rate constant, so I don't have a straight answer on the matter either.

Yup I was wondering about this myself!

 

[levyusupov]

i just posted the answer guys, check it out !!!!

 

[Mstoothlady2012]

Rate= K [A]

Keq = [A]/[C][D]

catalyst lowers the activation energy...hence the rate will be faster which in turn affects the rate constant K

Keq is not related to how the fast the reaction is...instead it is based on concentration.

That is how i understand it...i hope my explanation is not wrong! correct me pls if I am wrong😀

 

[PD3]

Thanks everyone. That makes sense.