- Joined
- Jun 23, 2010
- Messages
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- 21
Destroyer GC 140 in 2011 version, 132 in 2010 version.
I have a minor/stupid question on this problem:
"Consider hydrozoic acid, HN3. The Ka at 25 C is 2x10^-5. Which of these statements will be true if HN3 was put into solution?"
So the answer says that [N3-]=[H+] at eqlbm based off of the balanced reaction HN3(aq) +H2O(l) --> H3O+(aq) + N3- (aq).
Okay, I understand that, but based off of other solubility problems like finding the Ksp of BiI3(s) --> Bi + 3I- , why is is that the balanced reaction isn't written as:
HN3 --> H+ + 3N ? And so it would be [H+]=3[N-] at eqlbm?
Is it just cause N3 is a compound and it can't be broken up into 3N? But BiI3 was broken into 3I, not I3.....
I have a minor/stupid question on this problem:
"Consider hydrozoic acid, HN3. The Ka at 25 C is 2x10^-5. Which of these statements will be true if HN3 was put into solution?"
So the answer says that [N3-]=[H+] at eqlbm based off of the balanced reaction HN3(aq) +H2O(l) --> H3O+(aq) + N3- (aq).
Okay, I understand that, but based off of other solubility problems like finding the Ksp of BiI3(s) --> Bi + 3I- , why is is that the balanced reaction isn't written as:
HN3 --> H+ + 3N ? And so it would be [H+]=3[N-] at eqlbm?
Is it just cause N3 is a compound and it can't be broken up into 3N? But BiI3 was broken into 3I, not I3.....