Destroyer GC #28

[userah]

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I was wondering if someone could explain the formula he uses for the "quick trick" the Log [A]/ is the part throwing me off. I was trying to relate the trick to the actual equation for the problem. Is B supposed to be Hydrogen concentration? and if so what is A? the Oxygen? any help would be greatly appreciated. thank you

btw the actual equation for the problem is:
E = Eo - (.0591/n) * log (1/[H+]^4 [O]^2)

 

[cskpeter]

btw the actual equation for the problem is:
E = Eo - (.0591/n) * log (1/[H+]^4 [O]^2)

The equation is actually
E = Eo - (.0591/n) * log (1/[H+]^4 [O2]) since O2 is gas.

Don't be confused with the Log [A]/. Dr. Romano is throwing [A] & to specify numerator and denominator part. So from the above equation [A]=1 and =[H+]^4 [O2].

Now understand why E would increase when increases?
Bigger denominator (for the convenience, let's say it's bigger than 1) -> negative log value -> positive product added to Eo -> E increases