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Destroyer Gchem #130

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DENT2008

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I got in trouble for posting the exact question earlier, but here it goes again- not exactly as written....

when 200mL of .02 M KMnO4 reacts with zinc, how many mg of zinc are needed?


*I'm really confused on how they get .04mols of KMnO4/MnO4, I thought it was .01 mols... Please help, Thanks
 

bruinguy083

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M=Molarity=moles/liters. in this case, you have .2 liters. .2x.02 should get you .004 mols of kmno4.

how did you come up w/ .01? Hope this helps.
 

DENT2008

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ok, im seriously an idiot- i divided instead of multiplying... i've been staring at that problem for way too long to even see the obvious.

thanks!!
 
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