Destroyer gen chem #68

[joonkimdds]

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it says
"a 1 liter aqueous solution contains 18g of C6H12O6 and 3.2 g CH3OH. Find the mole fraction of C6H12O6"


Mole fraction = mol of X / mol of total

I was looking for mol of total.
so what I did was finding mol of C6H12O6, CH3OH and water add them up.

the solution says to find the mol of water, we use 1 L = 1000g and convert it into mol.


how do we know that there is 1L of water when the solution is 1L
it didn't say solvent is 1L, it says solution is 1L
so that means 1L is water + volume of other two solutes
and i don't understand why the answer key says we have 1L of water.

 

[arpitpatel86]

some1 correct me if im wrong on this....i think when they say in 1L solution....it contains the solvent bc solution= solvent plus solute......and whenever it says dissolved in solution go ahead and convert it to mols of h20 and add that on i had this problem on my kaplan test too and they did the same thing as this problem so im assuming u do it all the time unless they specify the solvent?

 

[joonkimdds]

some1 correct me if im wrong on this....i think when they say in 1L solution....it contains the solvent bc solution= solvent plus solute......and whenever it says dissolved in solution go ahead and convert it to mols of h20 and add that on i had this problem on my kaplan test too and they did the same thing as this problem so im assuming u do it all the time unless they specify the solvent?

Yes, solution contains both solute and solvent.
so it should be
Vol Solution = Vol solute + Vol solvent.
But my question is that how can the volume of solution equal to volume of solvent unless we completely ignore the volume of solute?

 

[joonkimdds]

bump~anyone?