The elements in Group I will have 1s1 , 2s1, 3s1....( 1 unpaired electron)
The elements in Group II will have 1s2 , 2s2 , 3 s2 ( no unpaired electron)
The elements in Group
III , IV, V, VI, VII , VIII
2p1 2p2 2p3 2p4 2p5 2p6
3p1 3p2 3p3 .................
4p1 ............................
The elements in group VIII has 6 electrons for 3 orbitals --> no unpaired electron ( noble gas)
The elements in group VII has 5 electrons for 3 orbitals --> 1 unpaired electron
The elements in group VI has 4 valence electrons for 3 orbitals --> 2 unpaired electron
The elements in group V has 3 valence electrons for 3 orbitals--> 3 unpaired electron
The transition metals will fall to d shell , and has 5 orbitals , which can fill up to 10 electron .
If you look at the periodictable , Cr, Fe , Cu are in the same row. Cr is in front of Fe and Cu . That means it need most electrong to fill up its shell . Or Cr has 4 unpaired electron and need 6 electron to fill up its shelf . Fe needs 2 more electrons to fill up its shell ; therefore , Fe has 2 unpaired electron . Cu needs 1 more electron to fill up its shell , therefore Cu has 1 unpaired electron.
So, for s shell the maximum unpaired electron is 1 .
For p shell the maximum unpaired electron is 3
For d shell the maximum unpaired electron is 5
For f shell the maximum unpaired electron is 7