Destroyer O Chem #43

Started by tawaqul
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tawaqul

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I'm having trouble understanding splitting.

It says that 3-pentanone has only a triplet and a quartet. I see those, but why doesn't the 2nd C next to the carbonyl also see a singlet? Doesn't the carbonyl show up as a singlet as the 2nd C views it? Is it possible for a carbon to see both?

I know this must be really basic, but I'm lost.

Thanks in advance 🙂
 
HNMR, is looking at Hs not Cs. 3-pentanone is symmetrical so the only Hs you would see on the spectrum are the CH3 Hs and the CH2 Hs which come out to be a triplet and quartet.
 
I'm having trouble understanding splitting.

It says that 3-pentanone has only a triplet and a quartet. I see those, but why doesn't the 2nd C next to the carbonyl also see a singlet? Doesn't the carbonyl show up as a singlet as the 2nd C views it? Is it possible for a carbon to see both?

I know this must be really basic, but I'm lost.

Thanks in advance 🙂

I could be wrong, but I think you're confusing H-NMR (proton NMR, "normal" NMR) with C-NMR?
The carbonyl carbon doesn't have any H's on it...😕

EDIT: tranv117.. ya beat me to it..
 
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Quick question. #73 on TopScore Test 1. I see that the OCH3's are equivalent and that they equal 1 singlet. BUT, it says that the other 4 aromatic protons = 1 singlet as well...this I don't get. They are equivalent, I see that, but on either side of any one aromatic proton, there is a H, which would make them more than a singlet....

Help please...