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Destroyer O chem question

Discussion in 'DAT Discussions' started by happyana, Dec 23, 2008.

  1. happyana

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    anyone know why A isn't the answer for #44? why wouldn't the reactivity of the halogens be taken into consideration? isn't I a weak base since it's conjugated acid is really strong, so that would make for a better leaving group?
     
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  3. Sublimation

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    I dont have destroyer, if you could post the question i could be of more help.
     
  4. drillbit

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    E is aromatic -the electron density is delocalized - which means it is more stable! The more stable the carbocation - the faster it reacts. I is a better leaving group, but you always have to take into account the structure of the compound. Cl is a good leaving group too - so there are no issues with it not allowing the formation of a carbocation.
     
  5. sciencegod

    sciencegod Super Member
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    that's like saying why does a methyl iodide not react faster than a t-butyl chloride. you gotta form the stablest carbonium ion. making the thing aromatic kicks the butt off I being a better leaving group. hope that hlps.
     
  6. Panther85

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    u pretty much nailed it. the aromaticity once the Cl leaves is the best carbocation structure.
     
  7. sciencegod

    sciencegod Super Member
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    what's wrong with what I said.
     

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