Destroyer OC question 89

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virajpatel

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I am using the 2013 DAT destroyer and if anyone has that could you look over it and explain to me why choice is not aromatic. Since the lone pair of electrons is delocalized it should be aromatic, to my understanding but destroyer begs to differ. Please explain.
 
There is 1 aromatic, 1 anti-aromatic, and 2 are non-aromatic. The explanation is pretty clear on the choices. The two non-aromatics have unconjugated sp3 carbons which make them neither anti or aromatic.
 
If you have an sp3 carbon, it is automatically non-aromatic. However, if you have all conjugated carbons and Hucker rule is not supported, then it is antiaromatic.
 
Yes but there is a lone pair that exists. If there is no double bond present next to the lone pair then it counts as pi electrons. Which was conjugated, sp2, planar and followed huckels rule
 
The Lone pairs only count as Pi electrons if they are inside the ring for noncarbon atoms and outside/inside for carbon atoms.
 
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