Destroyer ochem #52

[Erhatstil]

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If anyone has a few minutes and wouldn't mind explaining the answer to this question a bit more clearly, it would be great. I know most C=C are sp2, but this obviously isn't. the explanation says the "two pi bonds are mutually perpendicular and the central C is part of both. these two pi systems don't overlap." is this referring to the two pi bonds of the carbon with hydrogens? i can't visualize this...

 

[CadetTpt06]

Maybe mine is a different edition, my problem 52 is: Which is true concerning any R-enantiomer?

Not sure # your problem is

 

[joonkimdds]

I know this one.
C is surrounded by two, 2, TWO!!!!

 

[RHONDAROBINSON]

Looking at 1,3-dimethylcyclohexane having 2 chiral carbons, how many possible stereoisomers can be written. Can anyone help me with identifying stereoismers? I am having a problem with this part of Organic Chemistry and I just started studying.


Rhonda

 

[NeoAkira]

Looking at 1,3-dimethylcyclohexane having 2 chiral carbons, how many possible stereoisomers can be written. Can anyone help me with identifying stereoismers? I am having a problem with this part of Organic Chemistry and I just started studying.


Rhonda

There is a simply equation for how many stereoisomers one can have.

# of Stereoisomers possible = 2^n, where n = # of chiral centers (or chiral carbons/asymmetric carbons)

 

[NeoAkira]

If anyone has a few minutes and wouldn't mind explaining the answer to this question a bit more clearly, it would be great. I know most C=C are sp2, but this obviously isn't. the explanation says the "two pi bonds are mutually perpendicular and the central C is part of both. these two pi systems don't overlap." is this referring to the two pi bonds of the carbon with hydrogens? i can't visualize this...

I'm not sure i totally understand this question, but my interpretation is that the central carbon looks like this:

C=C=C, where the middle one is the central carbon. The tricky thing here is what do they mean by "mutual"? My interpretation is that the bonds are perpendicular in the same way. Therefore in the structure I've shown above there are 2 pi systems and they are both perpendicular to the central carbon in the same way.

I dunno if that helps, but that's how I interpret the problem.

 

[Erhatstil]

yeah i appreciate the response. for some reason the answer key was explaining the bond relationship of the carbon with the two hydrogens instead of focusing on the perpendicular bonds of the central carbon. this is why i was confused. thanks again

 

[Broncos85]

Hey guys this should be helpful:

http://forums.studentdoctor.net/showthread.php?t=496129&highlight=allene