T topdent1 Full Member 10+ Year Member 15+ Year Member Jul 16, 2008 #1 Advertisement - Members don't see this ad When using the reagent NBS, it adds to the allylic position. Does that mean it will ALWAYS add the reagent 3 carbons away from the double bond? And this can be from either side correct?
Advertisement - Members don't see this ad When using the reagent NBS, it adds to the allylic position. Does that mean it will ALWAYS add the reagent 3 carbons away from the double bond? And this can be from either side correct?
mddang Full Member 15+ Year Member Jul 16, 2008 #3 I don't really get what you're saying, but if we have c-c=c-c-c (numbered 1 on the left to 5 on the right), then it would add to either C-1 or C-4. Allylic means a carbon adjacent to a carbon involved in a double bond. Upvote 0 Downvote
I don't really get what you're saying, but if we have c-c=c-c-c (numbered 1 on the left to 5 on the right), then it would add to either C-1 or C-4. Allylic means a carbon adjacent to a carbon involved in a double bond.
klutzy1987 StudyingSucks Letsgo Mets 10+ Year Member 15+ Year Member Jul 17, 2008 #4 mddang said: I don't really get what you're saying, but if we have c-c=c-c-c (numbered 1 on the left to 5 on the right), then it would add to either C-1 or C-4. Allylic means a carbon adjacent to a carbon involved in a double bond. Click to expand... And in this case it would be C-4 because it is a secondary allylic. Upvote 0 Downvote
mddang said: I don't really get what you're saying, but if we have c-c=c-c-c (numbered 1 on the left to 5 on the right), then it would add to either C-1 or C-4. Allylic means a carbon adjacent to a carbon involved in a double bond. Click to expand... And in this case it would be C-4 because it is a secondary allylic.