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destroyer ochem #70
Started by silveryhair
this is a ketone; aldehydes and ketones do not undergo nucleophylic acyl substitution. The result of addition of H2O/H+ to ketones is a hydrate. In this case you have D2O which means on the hydrate the OD group will be present.
So, the product is Ph-C(OD)2-CH3
So, the product is Ph-C(OD)2-CH3
Yeah, so does anyone know why the hydrogen's are replaced by deuterium's?
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its actually similar to alpha halogenation of aldehydes and ketone via acid catalyzed mechanism. The reaction ocurs via enolat enolate ion formation. In McmMurry's the reagents are X2(halogens) + Acetic acid. If you use X2 with a Base like NaOH, it is going to lead to Haloform reaction and the products wud be Ph-COO- and CHX3.
Yeah, so does anyone know why the hydrogen's are replaced by deuterium's?
it's just heavy hydrogen; hydrogen with a neutron
Yeah, I know its a hydrogen isotope. I just don't see the mechanism of how the Hydrogens are replaced with the D since its not base catalyzed why would it remove the alpha hydrogens?
I think iremember this question, from the answers you can tell that the writer is after substitution reactions of alpha carbon. A couple of points, first of all in the real test the questions are very straight forward. Secondly, I think the author wants to empphasiE the. Difference between acid catalyzed and base catalyzzed substitutions of alpha carbon. My dat had a claisen but not something like this question. They. Like name reactions of alpha carbon. The answer I. Gavve above is a competing product with the correct answer. Too much details, not a standard question.
Yeah, I know its a hydrogen isotope. I just don't see the mechanism of how the Hydrogens are replaced with the D since its not base catalyzed why would it remove the alpha hydrogens?
First the oxygen of carbonyl is deuterated. Then a D2O molecule abstracts a hydrogen of methyl forming an enol making a double bond and neutralizing the plus charge on oxygen of carbonyl. Then a lone pair of OD makes a pi bond and the pi bond of enol abstracts a D. From a D3O molecule. I hope it makes sense, if not, pm me and I will send a pdf of the mechanism
First the oxygen of carbonyl is deuterated. Then a D2O molecule abstracts a hydrogen of methyl forming an enol making a double bond and neutralizing the plus charge on oxygen of carbonyl. Then a lone pair of OD makes a pi bond and the pi bond of enol abstracts a D. From a D3O molecule. I hope it makes sense, if not, pm me and I will send a pdf of the mechanism
Can you please post it on here? It'd be super helpful for everyone.
Thanks!
Can you please post it on here? It'd be super helpful for everyone.
Thanks!
I wrote a post about it a little while back:
http://masterorganicchemistry.wordpress.com/2010/05/05/another-awesome-example-of-acid-catalysis/
Hope this is helpful - James
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