Destroyer Ochem #80
Started by jjkim1232
The bulky base, the name says it... its bulky.. so it rather rip off a hydrogen thats easier to reach. In this case, the terminal hygrogens on Carbon 1 (primary), are much easier to rip, than the hydrogen from Carbon 3 (secondary).
Kaplan blue book page 363 (towards the bottom) says:
"Often there are two possible products. In such a case, the more substituted double bond is formed preferentially."
So I am assuming the above statement does not apply when dealing with a bulky base in which case the less substituted product ALWAYS results??
"Often there are two possible products. In such a case, the more substituted double bond is formed preferentially."
So I am assuming the above statement does not apply when dealing with a bulky base in which case the less substituted product ALWAYS results??
Yes sir. The bulky base produces the least substituted product, where as a smaller, less bulky base produces the most substituted product.
I believe if you continue doing destroyer, you will get a hang of it because there are more problems involving this.
Good luck.
I believe if you continue doing destroyer, you will get a hang of it because there are more problems involving this.
Good luck.
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