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Hey, guys.
So in problem 78, I don't understand why the double bond forms where it forms (after being treated with a hindered base ) instead of forming d.b. in the ring on the alpha C to where CH3 and Br are at. I thought E2 favor more stable alkene formation.
So in problem 78, I don't understand why the double bond forms where it forms (after being treated with a hindered base ) instead of forming d.b. in the ring on the alpha C to where CH3 and Br are at. I thought E2 favor more stable alkene formation.