Destroyer Probability Question

[emminent]

---

Members don't see this ad.

Four dice are rolled. What is the probability of getting exactly two 1's and two 6's in any order?

I read the explanation which is 6*(1/6)^4

I understood the (1/6)^4 but not the multiplying 6 portion.

Can someone break it down in a different way?

 

[DocVaquero]

The 1/6^4 is the probability of getting 1 then 1 then 6 then 6. Since it says it can be any order, we have to multiply by six due to the six different orders. These would be (1166)(1616)(1661)(6611)(6161)(6116). So the idea is multiplying the probability of getting any order. Hope this helps!

 

[emminent]

Thanks