Destroyer'13 gc q135

[hope_to_match]

Advertisement - Members don't see this ad

135. If 20 mL of 0.012 M solution of Ca(OH)2 is added to 48 mL of HBr, what is the concentration?

The solution in the back says:


Ca(OH)2 has 2 OH's and HBr has 1 H, thus we can't use M1V1=M2V2 and have to use Normality....

now my question is: if the amount of OH's and H's equal- can we use M1V1=M2V2???

thanks

 

[Illfavor]

135. If 20 mL of 0.012 M solution of Ca(OH)2 is added to 48 mL of HBr, what is the concentration?

The solution in the back says:


Ca(OH)2 has 2 OH's and HBr has 1 H, thus we can't use M1V1=M2V2 and have to use Normality....

now my question is: if the amount of OH's and H's equal- can we use M1V1=M2V2???

thanks

Yep.

 

[UHmalgam]

Instead of using normality, can we just multiply .012 x2 since there are 2 OH giving us .024 as the concentration for OH-. Then, using M1V1=M2V2 to get the answer?

 

[UHmalgam]

I would rather do it that way...never really like the N normality stuff to begin with.