F FlipDoc2Be Full Member 10+ Year Member Joined Feb 10, 2010 Messages 17 Reaction score 0 Points 0 Apr 25, 2010 #1 Advertisement - Members don't see this ad Nvm. Thanks! Last edited: Apr 25, 2010
J joshto Nervous&Neurotic 15+ Year Member Joined Jan 30, 2006 Messages 267 Reaction score 0 Points 0 Pre-Medical Apr 25, 2010 #2 c-4 on the galactose does not have a free hydroxyl, thus it cannot be methylated, thus the answer cannot be A. as per your question, isn't the acetal group the linkage? (i.e. aren't they one in the same) Upvote 0 Downvote
c-4 on the galactose does not have a free hydroxyl, thus it cannot be methylated, thus the answer cannot be A. as per your question, isn't the acetal group the linkage? (i.e. aren't they one in the same)
