Discussions for NBME Questions

[MudPhud20XX]

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Hi all, so I thought it would be a good idea to have a designated thread for NBME questions.

Please feel free to use this thread. Many thanks....

So here is the first question! Give it a shot!

View attachment 185150

 

[SBR249]

It's a competitive antagonist.

You should know that most NBME forms have their own individual designated threads and you should search for those. Also straight up posting cropped screenshots of NBME questions may be a copyright violation.

Finally, if you are just starting MS2, then using NBMEs now may be a waste since they are designed to gauge your progress when you are reviewing for the boards and it's a finite resource.

 

[MudPhud20XX]

you're right. I got rid of the snapshot. I wanted to post the figure so I had to give a snapshot. Thanks for the advise.

By the way, I think the answer is not competitive antagonist. If you look at the x axis, it was actually negative dose. I think the answer is full agonist. Could you please confirm this?

 

[SBR249]

Nope, it's still a competitive antagonist. If you look at the x-axis, you'll notice that even though the units are -log[Dose A], the numbers are decreasing from left to right. A small number in this case means a larger dose of Drug A. Put another way, mathematically, 10^-10 is a smaller dose than 10^-5. So Dose A still increases from left to right.

Given that, the plot fits that of a competitive antagonist.

If it were a full agonist, you'd see an increase in apparently potency of drug A not a decrease.

 

[MudPhud20XX]

Nope, it's still a competitive antagonist. If you look at the x-axis, you'll notice that even though the units are -log[Dose A], the numbers are decreasing from left to right. A small number in this case means a larger dose of Drug A. Put another way, mathematically, 10^-10 is a smaller dose than 10^-5. So Dose A still increases from left to right.

Given that, the plot fits that of a competitive antagonist.

If it were a full agonist, you'd see an increase in apparently potency of drug A not a decrease.

You're right. Dang, I thought I got away with their trick, but I was still fooled! Thank you.