Does anyone know why Mg2+ can't be further oxidized?

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deleted647690

This is in reference to a question in BR, which asks "Which of the following species is the strongest reducing agent?
A. Cl2
B. Cu
C. Mg2+
D. Zn"

The answer is Zn. I would have thought Mg2+, because if it loses another electron, it reaches a stable form, so I would think oxidation is preferred. Plus, according to the table they give, the oxidation potential for Mg is 2.37, which is greater than that given for Zn. Their reasoning for why it wasn't Mg2+ was that it cannot be further oxidized.


I guess the reaction given in the table would give you the oxidation potential for Mg and not Mg2+, so we don't really know the oxidation potential for Mg2+. However, I still don't see how the noble gas stability reasoning doesn't work
 
Even if you're not a chemist, it's a good idea to have an idea of what common ions are, i.e. Mg2+, Zn2+, Cu+, Cu2+, Na+, K+, Cl-, etc.
 
If the forward half-reaction is mg2+ + 2e- --> Mg , why is the reverse rxn not Mg - 2e- --> Mg2+ ? I understand that Mg2+ is already in noble gas configuration, but thought the reverse reaction and corresponding value would have referred to Mg?
 
If the forward half-reaction is mg2+ + 2e- --> Mg , why is the reverse rxn not Mg - 2e- --> Mg2+ ? I understand that Mg2+ is already in noble gas configuration, but thought the reverse reaction and corresponding value would have referred to Mg?
Never mind, answered my own question- just needed to read more carefully.
 
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